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6 April, 10:22

Find two positive consecutive integers whose product is 132.

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  1. 6 April, 13:54
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    If x is the first integer, then x+1 is the second. x (x+1) = 132 or x^2+x-132=0. This factors as (x-11) (x+12) = 0. Thus either x=11 or x=-12

    So either 11 and 12 or - 12 and - 11 will do.
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