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26 January, 19:08

Factorise 2y^2 + y + 6xy + 9x - 3

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  1. 26 January, 21:58
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    Answer: (2y+3) (3x+y-1)

    Step-by-step explanation:

    First regroup the terms.

    6xy+9x+2y^2+y-3

    Second factor 3x out of 6xy+9x

    3x (2y) + 9x+2y^2+y-3

    3x (2y) + 3x (3) + 2y^2+y-3

    And you get

    3x (2y+3) + 2y^2+y-3

    Third factor by grouping
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