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Luci
26 January, 19:08
Factorise 2y^2 + y + 6xy + 9x - 3
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Gauge
26 January, 21:58
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Answer: (2y+3) (3x+y-1)
Step-by-step explanation:
First regroup the terms.
6xy+9x+2y^2+y-3
Second factor 3x out of 6xy+9x
3x (2y) + 9x+2y^2+y-3
3x (2y) + 3x (3) + 2y^2+y-3
And you get
3x (2y+3) + 2y^2+y-3
Third factor by grouping
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