Ask Question
5 July, 18:58

Suppose that X is the number of bears spotted by tourists to Banff, Canada. The table below is the probability distribution for X. What is the expected value of X, that is, what is the mean of its distribution?

X 0 1 2 3 4

Probability 0.2 0.1 0.4 0.15 0.15

+3
Answers (1)
  1. 5 July, 20:46
    0
    Expected value of X = 1.95

    Step-by-step explanation:

    Expected value of X, E (X) = ∑XP (X)

    ∑ = Summation

    X = number of bears spotted

    P (X) = probability of a certain number of bears spotted

    E (X) = (0*P (X=0)) + (1*P (X=1)) + (2*P (X=2)) + (3*P (X=3)) + (4*P (X=4))

    E (X) = (0*0.2) + (1*0.1) + (2*0.4) + (3*0.15) + (4*0.15)

    E (X) = 0 + 0.1 + 0.8 + 0.45 + 0.60 = 1.95
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Suppose that X is the number of bears spotted by tourists to Banff, Canada. The table below is the probability distribution for X. What is ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers