At 1:30 marlon left his house to go to the beach a distance of 5.25 miles. He rode his skateboard until 2:15 and then walked the rest of the way. He arrived at the beach at 3:00. Marlon's speed on his skateboard is 2.5 times his walking speed. Find his speed when skateboarding and when walking.

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Mathematics

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13 January, 04:55

At 1:30 marlon left his house to go to the beach a distance of 5.25 miles. He rode his skateboard until 2:15 and then walked the rest of the way. He arrived at the beach at 3:00. Marlon's speed on his skateboard is 2.5 times his walking speed. Find his speed when skateboarding and when walking.

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Khalil Clark · Answer 1

Answer: his speed when skateboarding 5 mph and when walking is 2 mph

Step-by-step explanation:

Marlon started riding his skateboard from his house at 1:30 until 2:15 when he started walking. This means that the time he spent riding his skateboard is

2:15 - 1:30 = 45 minutes

Converting 45 minutes to hours, it becomes

45/60 = 0.75 hour

He walked the rest of the way. He arrived at the beach at 3:00. This means that the time he spent walking is

3:00 - 2:15 = 45 minutes

Converting 45 minutes to hours, it becomes

45/60 = 0.75 hour

Let x represent Marlon's walking speed.

Marlon's speed on his skateboard is 2.5 times his walking speed. This means that his speed when skateboarding is 2.5x

Distance = speed * time

Distance covered while walking is

x * 0.75 = 0.75x

Distance covered while skateboarding is

2.5x * 0.75 = 1.875x

Since the total distance to the beach is 5.25 miles, then

0.75x + 1.875x = 5.25

2.625x = 5.25

x = 5.25/2.625

x = 2mph

His speed while skateboarding is

2.5x = 2.5 * 2 = 5mph