Suppose that X is the number of hours that a computer is used in a computer lab on campus. The table below is the probability distribution for X. What is the expected value of X, that is, what is the mean its distribution? X 0 1 2 3 4Probability 0.2 0.2 0.4 0.15 0.05A. 0.8 B. 1.0 C. 1.65 D. 2

Option C: E (X) = 1.65

Step-by-step explanation:

Expected value of X, E (X) = ∑XP (X)

∑ = Summation

X = number of hours

P (X) = probability of a certain number of hours

E (X) = (0*P (X=0)) + (1*P (X=1)) + (2*P (X=2)) + (3*P (X=3)) + (4*P (X=4))

E (X) = (0*0.2) + (1*0.2) + (2*0.4) + (3*0.15) + (4*0.05)

E (X) = 0 + 0.2 + 0.8 + 0.45 + 0.20 = 1.65

E (X) = 1.65 - Option C