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18 March, 15:11

The axis of symmetry for the graph of the function is f (x) = 1/4 x2 bx 10 is x = 6. what is the value of b?

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  1. 18 March, 16:55
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    F (x) = 1/4 x^2 + bx + 10 = 1/4 (x^2 + 4bx + 40) = 1/4 (x^2 + 4bx + 4b^2 + 40 - 4b^2) = 1/4 (x + 2b) ^2 + 1/4 (40 - 4b^2) = 1/4 (x + 2b) ^2 + 10 - b^2

    Axis of symmetry is x = 6 implies that 2b = 6

    Therefore, b = 6/2 = 3
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