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8 March, 08:02

Four times a number added to 3 times a larger number is 31. Seven subtracted from the larger number is equal to twice the

smaller number. Let x represent the smaller number and y represent the larger number. Which equations represent this

situation?

O y=-x+31

y = 2x + 7

oy - 3x + 1

y - 2x+7

o y--*x+31

y=-2x+7

+1
Answers (1)
  1. 8 March, 09:53
    0
    The complete options are missing.

    Step-by-step explanation:

    The system of equations for this problem is:

    4x + 3y = 31

    y - 7 = 2x

    Best Regards!
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