Stephen buys a bag of cookies that contains 9 chocolate chip cookies, 7 peanut butter

cookies, 6 sugar cookies and 7 oatmeal cookies. What is the probability that Stephen

randomly selects a sugar cookie from the bag, eats it, then randomly selects a peanut

butter cookie? Express you answer as a reduced fraction.

The probability that Stephen randomly selects a sugar cookie from the bag and eats it, then randomly selects a peanut butter cookie is 3/58 (or) 0.052

Step-by-step explanation:

The bag of cookies contain 9 chocolate chip cookies, 7 peanut butter

cookies, 6 sugar cookies and 7 oatmeal cookies.

The total number of cookies in the bag = 9+7+6+7 = 29 cookies.

It is given that, Stephen randomly selects a sugar cookie from the bag and eats it.

The probability to select a sugar cookie = No. of sugar cookies / total

⇒ 6/29

After that, he randomly selects a peanut butter cookie. We know that the bag now contains 1 cookie less than the total cookies because Stephen ate one sugar cookie.

Therefore, the total number of cookies in the bag = 28 cookies.

Probability to select a peanut butter cookie = No. of peanut cookies / total

⇒ 7/28

⇒ 1/4

The total probability = P (sugar cookie) * P (peanut cookie)

⇒ (6/29) * (1/4)

⇒ 6/116

⇒ 3/58 (or) 0.052