A small airline company employs 11 male flight attendants and

13female flight attendants. As an economy move, the

managementdecides to fire 2 workers. Find the probability

that

a. both fired workers will be male flight attendants.

b. one of the fired workers will be a male flight attendant and

theother will be a female flight attendant.

a) There is a 19.93% probability that both fired workers will be male flight attendants.

b) There is a 51.81% probability that one of the fired workers will be a male flight attendant and the other will be a female flight attendant.

Step-by-step explanation:

a. both fired workers will be male flight attendants.

Initially there are 24 attendants, of which 11 are male and 13 are female.

So the probability that the first fired worker will be male is 11/24.

Now there are are 23 workers, of which 10 are male.

So, in this case, the probability that the second worked fired is also male is 10/23.

The probability is:

(11/24) * (10/23) = 0.1993

There is a 19.93% probability that both fired workers will be male flight attendants.

b. one of the fired workers will be a male flight attendant and the other will be a female flight attendant.

Male then female

Initially there are 24 attendants, of which 11 are male and 13 are female.

So the probability that the first fired worker will be male is 11/24.

Now there are are 23 workers, of which 13 are female.

So, in this case, the probability that the second worked fired is a female is 13/23.

Female then male

Initially there are 24 attendants, of which 11 are male and 13 are female.

So the probability that the first fired worker will be female is 13/24.

Now there are are 23 workers, of which 11 are male.

So, in this case, the probability that the second worked fired is male is 11/23.

The sum of these probabilities is:

P = (11/24) * (13/23) + (13/24) * (11/23) = 0.5181

There is a 51.81% probability that one of the fired workers will be a male flight attendant and the other will be a female flight attendant.