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15 September, 04:29

a rectangle has an area of 320 feet squared. the length is 4 feet longer than the width. find the dimensions.

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  1. 15 September, 04:49
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    Width of the rectangle is 16 ft and length of the rectangle is 20 ft

    Step-by-step explanation:

    Step 1:

    Given area of the rectangle = 320 ft². Let the width of the rectangle be x, then the length = x + 4. Use the formula for area of a rectangle = (length * width)

    320 = x (x + 4)

    320 = x² + 4x

    x² + 4x - 320 = 0

    x = (-b ±√b² - 4ac) / 2a = (-4 ±√16 - 4*1*-320) / 2

    = (-4±√1296) / 2 = (-4 ± 36) / 2

    = 32/2, - 40/2 = 16, - 20 (neglecting the negative value)

    ∴ Width of the rectangle = 16 ft

    ∴ Length of the rectangle = 16 + 4 = 20ft
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