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29 January, 20:59

Box A has 4 times as many sweets as box B and thrice as many sweets as box C. If there were 38 sweets in the 3 boxes, how many sweets were in box A?

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  1. 30 January, 00:12
    0
    24

    Step-by-step explanation:

    A is 4 times that of B ie

    A = 4B (1)

    A is also 3 times that of C ie

    A = 3C (2)

    From equation 1,

    B = A/4

    From equation 2,

    C = A/3

    But the there are 38 sweets in the 3 boxes i. e

    A + B + C = 38

    A + A/4 + A/3 = 38

    Multiply through by 12 to express in linear form

    12A + 3A + 4A = 456

    19A = 456

    Dive both side by 19

    A = 456/19

    A = 24
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