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11 December, 21:58

The interior angles formed by the sides of a pentagon have measures that sum to 540°. What is the measure of angle B? Enter your answer in the box. m∠B = ° An irregular pentagon labeled ABCDE with angle A one hundred thirty degrees, angle D seventy five degrees, angle B parenthesis x minus five parenthesis degrees, angle C parenthesis x plus thirty parenthesis degrees, angle E parenthesis x minus thirty five parenthesis degree

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  1. 11 December, 23:46
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    the answer is 110

    Step-by-step explanation:

    In a regular pentagon the angles are 112. Take that number and replace x with 112

    112-5 = 107

    112+30 = 142

    112-35 = 77

    Take those three numbers and subtract them from the sum 540 provided as a total of all five angles.

    540-107-142-77-130-75 = 9

    You have 3 missing angles.

    Nine divided by three is three.

    Add three to each of the numbers you got for the missing angles.

    107+3=110

    142+3=145

    77+3=80

    Those are your missing angles.

    I'm sure there is an shorter way of explaining it but this is how I did it and I got a 100 on the test.
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