In how many different ways can robert order 3 objects from a set of 8 objects?

Step-by-step explanation:

If the order of the objects doesn't matter (ABC is considered the same as CBA), then the number of combinations is:

₈C₃ = 8! / (3! (8-3) !) = 56

If the order does matter (ABC is considered different than CBA), then the number of permutations is:

₈P₃ = 8! / (8-3) ! = 336