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20 January, 15:11

How do you find the vertex of the equation y = (x-3) ^2+2?

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Answers (2)
  1. 20 January, 17:10
    0
    this is my explanation

    Step-by-step explanation:

    Graph the parabola using the direction, vertex, focus, and axis of symmetry.

    Direction: Opens Up

    Vertex:

    (

    3

    ,

    2

    )

    Focus:

    (

    3

    ,

    9

    4

    )

    Axis of Symmetry:

    x

    =

    3

    Directrix:

    y

    =

    7

    4

    x

    y

    1

    6

    2

    3

    3

    2

    4

    3

    5

    6

    ...
  2. 20 January, 18:09
    0
    Step-by-step explanation:

    put x-3=0

    x=3

    when x=3, y=2

    so vertex is (3,2)
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