A water tank holds 24,000 gallons. how many hours will it take for 2/3 of the water to be used if the water is used at an average rate of 650 gallons per day

In the question, it is already mentioned that the water tank holds = 24,000 gallons

In the given question it is also mentioned that the need is to find the time required to use 2/3 of the total water that the tank holds.

So the need is to find the amount of water that equals 2/3 of the total water in the tank.

Then

Quantity of water that needed to be used = [24000 * (2/3) ] gallons

= 16000 gallons

In the problem it is also mentioned that the average rate of consumption per day is 650 gallons.

So

650 gallons of water used in = 24 hours

16000 gallons of water will be used in = [ (24/650) * 16000] hours

= 590.77 hours

So the time required to consume 2/3 of the total water in the tank is 590.77 hours.