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6 November, 08:01

4x^2-16x-5 can be written in vertex form f (x) = a (x-h) ^2+k.

What are the values of a, h, and k.

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  1. 6 November, 09:15
    0
    h=2

    a=4

    k = - 21

    Step-by-step explanation:

    your h and k are vertex. h = x coordinate of vertex and k = y

    so formula for vertex coordinates is x = - b/2a and y = (4ac-b²) / 4a

    your a b c are 4 - 16 and - 5 respectively according to the main equation

    your a is concavity which is the same number as the 'a' of the equation
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