Can you distribute the 2 in 2 (x-3) (4x-1) to get (2x-6) (8x-2) ?

Question

Mathematics

Myles Ellison

19 June, 00:22

Can you distribute the 2 in 2 (x-3) (4x-1) to get (2x-6) (8x-2) ?

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Answers (1)

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Spencer Schmitt · Answer 1

Step-by-step explanation:

No you cannot do that. The 2 is only being multiplied in once. If you distribute it into each set of parenthesis, you have multiplied it in twice. Multiply it into only one set of parenthesis and then FOIL to get the polynomial expression. Or you can FOIL the 2 sets of parenthesis first and then multiply the 2 in at the end. Either way, you'll get the answer you need.