20 = -16t^2+36t

What is the answer

Step-by-step explanation:

16t^2-36t+20=0

a = 16; b = - 36; c = + 20;

Δ = b2-4ac

Δ = - 362-4·16·20

Δ = 16

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

t1=-b-Δ√2at2=-b+Δ√2a

Δ--√=16--√=4

t1=-b-Δ√2a = - (-36) - 42∗16=3232=1

t2=-b+Δ√2a = - (-36) + 42∗16=4032=1+1/4