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8 March, 06:24

Solve the problem by multiplying first. A clothing store is having a sale on shirts and jeans. Four shirts and two pairs of jeans cost $64. Five shirts and three pairs of jeans cost $87. The system of equations models this situation, where s is the cost of a shirt and j is the cost of a pair of jeans. How much does one shirt and one pair of jeans cost? 4s + 2j = 64 5s + 3j = 87

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  1. 8 March, 06:55
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    We will solve this by suing simultaneous equations,

    ⇒ 5s + 3j = 87

    4s + 2j = 64

    Multiply the first equation with 4 and the second one with 5, this is to get one of the values equal so that we can cancel them out,

    ⇒ (5s + 3j = 87) * 4

    (4s + 2j = 64) * 5

    ∴ ⇒ 20s + 12j = 348

    20s + 10j = 320

    Subtract both the equations. This is how your result (after subtraction) should look like,

    ⇒ 2j = 28

    ∴ ⇒ j = $14

    Now replace the value of 'j' in one of the original equations,

    ⇒ 4s + 2 (14) = 64

    ⇒ 4s + 28 = 64

    ⇒ 4s = 64 - 28

    ⇒ 4s = 36

    ∴ ⇒ s = $9

    Therefore, one pair of jeans cost $14 and a shirt costs $9

    Hope you understood! Feel free to ask me if you didn't understand a step.
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