Whats the answer to 2y^0 - (3y) ^0

1

Step-by-step explanation:

To answer this question, we need to that any number (except zero) raised to power 0 is equal to 1. With that in mind, let's solve this:

2y^0 - (3y) ^0

= 2 (1) - (1)

= 1

Note: 2y^0 = 2 (y^0) = 2 (1) = 2 whereas

(2y) ^0 = 1