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6 August, 01:22

Whats the answer to 2y^0 - (3y) ^0

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  1. 6 August, 04:09
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    Step-by-step explanation:

    To answer this question, we need to that any number (except zero) raised to power 0 is equal to 1. With that in mind, let's solve this:

    2y^0 - (3y) ^0

    = 2 (1) - (1)

    = 1

    Note: 2y^0 = 2 (y^0) = 2 (1) = 2 whereas

    (2y) ^0 = 1
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