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16 August, 19:14

A sandwich shop is ordering apples and grapes to make chicken salad. Apples cost $2.19 per pound and grapes cost $2.60 per pound. If they ordered a total of 20 pounds of apples and grapes and paid $35.80, how many pounds of grapes did they order?

We got $19.51 but we think it is wrong.

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Answers (1)
  1. 16 August, 21:14
    0
    Less than 13 pounds of grapes,

    as 14 pounds of grape exceeds $35.80,

    If you order as low as zero pounds of grapes, then the price of apple pounds would be $35.80/20 = $1.79 per pound

    Step-by-step explanation:

    Let

    Quantity of Apple and grapes=20

    Cost of apple=$2.19

    Cost of grape=$2.60

    Total cost of apple and grape=$35.80

    a+g=20

    a=20-g

    PaQa+PgQg=35.80

    2.19 (20-g) + 2.60g=35.80

    43.8-2.19g+2.60g=35.80

    0.41g=35.80-43.8

    0.41g=-8

    g=-8/0.41

    g = - 19.51

    PaQa+PgQg=35.80

    2.19a+2.60 (-19.51) = 35.80

    2.19a-50.726=35.80

    2.19a=35.80+50.726

    2.19a=86.526

    a=86.526/2.19

    =39.51

    PaA+PgG=35.80

    Pa (20-G) + 2.60G=35.80

    35.80/2.60 = 13.77 pounds of grapes, but no money will be left to buy apples, unless Pa=0

    G<13.77
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