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14 September, 13:50

Find the derivative of the function.

y=x^2lnx^2

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Answers (1)
  1. 14 September, 16:14
    0
    Correct answer: y = 2x (㏑x² + 1)

    Step-by-step explanation:

    We will use the product rule for this derivation

    Let be x² = U and ㏑x² = V

    Product rule is:

    dy = dU · V + U · dV

    y = 2x · ㏑x² + x² · 1/x² · 2x = 2x · ㏑x² + 2x = 2x (㏑x² + 1)

    y = 2x (㏑x² + 1)

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