A king decided to share his collection of precious rubies with his three daughters. He gave his oldest

daughter, Clara, 20% of the rubies. He gave Harriet, his middle daughter, 25% of those that were left. He

gave his youngest daughter, Melissa, 30% of the remaining rubies. After each daughter had received her

share, the king saw that there were 21 rubies left in his collection,

FET 75%

How many rubies did the king have in his collection to begin with?

How many did each daughter receive?

Question

Mathematics

Guest

15 August, 22:33

A king decided to share his collection of precious rubies with his three daughters. He gave his oldest

daughter, Clara, 20% of the rubies. He gave Harriet, his middle daughter, 25% of those that were left. He

gave his youngest daughter, Melissa, 30% of the remaining rubies. After each daughter had received her

share, the king saw that there were 21 rubies left in his collection,

FET 75%

How many rubies did the king have in his collection to begin with?

How many did each daughter receive?

+5

Answers (1)

Know the Answer?

Hayley Wolf · Answer 1

Suppose king has 100% of rubies and he decided to give 20% away so he's left with 80%. After that he decided to give 25% of 80% so he's left with 60% of the total rubies. Moreover he distributed 30% of the 60% he had finally he has only 42% of the original left with him that totalled to 21

42x/100=21

x=50

King had total 50 rubies

First daughter share = 50*20% = 10

Second daughter share = 40*25% = 10

Third daughter share = 30*30% = 9