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19 March, 08:50

Solve 5x^2-4x-2=0 by completing the square

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  1. 19 March, 09:48
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    Hello

    Here's the answer:

    2x^2 + 5x + 2 = 0/ / 2x^2+4x+x+2=0/ / 2x (x+2) + 1 (x+2) = 0/ / (2x+1) (x+2) = 0/ / x=-/frac{1}{2} / vee x=-2

    x^2-4x+1=0/ / x^2-4x+4-3=0/ / (x-2) ^2=3/ / x-2 = / sqrt3 / vee x-2=-/sqrt3/ / x=2+/sqrt3 / vee x=2-/sqrt3
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