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24 October, 02:40

You need a 70% alcohol solution. On hand, you have a 840 mL of a 95% alcohol mixture. How much pure water will you need to add to obtain the desired solution?

___mL of pure water to obtain

___mL of the desired 70% solution.

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  1. 24 October, 05:13
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    Step-by-step explanation:

    If x is the volume of pure water:

    Initial + added = final

    0.95 (840) + 0 (x) = 0.70 (840 + x)

    798 = 588 + 0.70 x

    x = 300

    840 + x = 1140

    You need to add 300 mL of pure water to obtain 1140 mL of the desired 70% solution.
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