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11 August, 22:28

What is the standard form of y = - (x-2) (x-3) (x-2) ?

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  1. 12 August, 00:38
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    y=-x^3+7x^2-16x+12

    Step-by-step explanation:

    y = - (x-2) (x-3) (x-2)

    y = - (x^2-2x-3x+6) (x-2)

    y = - (x^2-5x+6) (x-2)

    y = - (x^3-5x^2+6x-2x^2+10x-12)

    y = - (x^3-7x^2+16x-12)

    y=-x^3+7x^2-16x+12
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