What is the standard form of y = - (x-2) (x-3) (x-2) ?

y=-x^3+7x^2-16x+12

Step-by-step explanation:

y = - (x-2) (x-3) (x-2)

y = - (x^2-2x-3x+6) (x-2)

y = - (x^2-5x+6) (x-2)

y = - (x^3-5x^2+6x-2x^2+10x-12)

y = - (x^3-7x^2+16x-12)

y=-x^3+7x^2-16x+12