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7 February, 19:50

A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t

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  1. 7 February, 22:54
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    A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass-spring system is disturbed from its rest state by the force F (t) = 20 cos (8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.

    Determine the spring constant k.

    Answer:

    Spring Constant = 1000Nm^-1

    Step-by-step explanation:

    Given

    Mass = 10kg

    Spring Extension = 9.8cm

    Spring Constant K = Force/Extension

    Force = Mass * Acceleration

    Force = 10 * 9.8 = 9.8N

    Spring Extension = 9.8 cm = 9.8 / 100 = 0.098 m

    Spring constant = 98 / 0.098

    Spring Constant = 1000Nm^-1
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