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12 March, 09:37

You shuffle a standard 52 card deck of cards, so that any order of the cards is equally likely, than draw 4 cards. How many different ways are there to make that draw, where you care about the order

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  1. 12 March, 13:27
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    270725 different ways

    Step-by-step explanation:

    The problem tells us that the order of the letters does not matter. Therefore, in the combination the order is NOT important and is signed as follows:

    C (n, r) = n! / r! (n - r) !

    We have to n = 52 and r = 4

    C (52, 4) = 52! / 4! * (52-4) ! = 52! / (4! * 48!) = 270725

    Which means that there are 270725 different ways in total to make that raffle
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