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19 July, 07:04

My number has a tens digit that is 8 more than the ones digits. zero is not one of my digits.

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  1. 19 July, 08:59
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    91

    Step-by-step explanation:

    Let the tens digit of my number is x and the ones digit is y.

    Hence, the number is 10x + y ... (1)

    Now, it is given that, the ones digit is 8 less than the tens digit,

    Hence, x = y + 8 ... (2)

    Since the digits x and y can not be of two-digit i. e. they are less than 10 and x and y none of them can be zero, then fro equation (2), the only combination of x and y are 9 and 1.

    Therefore, the number is (10 * 9) + 1 = 91. (Answer)
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