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17 September, 23:59

If (a^3+27) = (a+3) (a^2+ma+9) then m equals

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  1. 18 September, 02:49
    0
    m = - 3

    Step-by-step explanation:

    a³ + 27 ← is a sum of cubes and factors in general as

    a³ + b³ = (a + b) (a² - ab + b²), thus

    a³ + 27

    = a³ + 3³

    = (a + 3) (a² - 3a + 9)

    comparing a² - 3a + 9 to a² + ma + 9, then

    m = - 3
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