11. A carousel has a diameter of 50 feet. To the nearest foot, how far does a child

seated near the outer edge travel when the carousel makes 8

revolutions?

1257 ft.

50 x 3.14 = 157.1

8 x 157.1 = 1257

1256 ft

Step-by-step explanation:

The circumference of a circle tell us how long is the line which enclose the circle. So, after 1 revolution a child seated near the outer edge travels a distance equal to the circumference of the carousel. If 8 revolutions are made the distance travelled will be 8 times the circumference.

Circumference = π · diameter = π · 50 ft = 157 ft

Distance travelled = 8 · 157 ft = 1256 ft