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4 September, 22:57

Find three consecutive numbers such

that three times the first number is

equal to 9 more than the sum of the

other two.

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Answers (1)
  1. 4 September, 23:38
    0
    3N = N + 1 + N + 2 + 9

    N = 12

    so 12, 13, 14? Been awhile since I've done this so that could be incorrect very sorry if it is
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