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18 April, 16:18

In our industry on average a firm paid out record year end bonuses of $125,500 per employee for 2008. We would like to take a sample of employees at our firm to see whether the mean year end bonus is different from the reported mean of $125,500 for the population. We sample 40 of our employees and we had a mean of $118,000. Assume a population standard deviation of $30,000. Setup for the p-value and critical value approaches. We want to be 95% confident about our finding.

If the Answer could be broken down on how they were solved, that would be great.

1. Sample Mean =

2. Population Mean = ?

3. Population Standard Deviation = ?

4. Sample size = ?

5. Alpha Error = ?

6. Confidence Coefficient = ?

7. Calculate Test Statistic = ?

8. Rejection Region Critical Value = ?

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Answers (1)
  1. 18 April, 17:02
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    Step-by-step explanation:

    Given that in our industry on average a firm paid out record year end bonuses of $125,500 per employee for 2008. We would like to take a sample of employees at our firm to see whether the mean year end bonus is different from the reported mean of $125,500 for the population.

    1. Sample Mean = 118000

    2. Population Mean = 125500

    3. Population Standard Deviation = 30000

    4. Sample size = 40

    5. Alpha Error = 5%

    6. Confidence Coefficient = 95%

    7. Calculate Test Statistic = Mean difference / s td error = - 1.581

    8. Rejection Region Critical Value = If Z statistic is below - 1.96 or above 1.96
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