The angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately 10.4degrees. If skyscraper B is 1472 feet tall, how far apart are the two skyscrapers? Assume the bases of the two buildings are at the same elevation.

8020 feet

Step-by-step explanation:

The tangent relation can be used to answer this question, since it relates the sides of a right triangle to the acute angle.

tan (elevation angle) = (1472 ft) / (distance between)

Then ...

distance between = (1472 ft) / tan (10.4°) ≈ 8020 ft

The skyscrapers are 8020 feet apart.