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31 December, 12:50

In a certain city, 27% of the families have a MasterCard, 19% have an American Express card, and 22% have a Visa card. Nine percent of the families have both a MasterCard and an American Express card. Fourteen percent have both a Visa card and a MasterCard. Six percent have both an American Express card and a Visa card. What is the probability of selecting a family that has either a Visa card or an American Express card?

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  1. 31 December, 13:14
    0
    35%

    Step-by-step explanation:

    Data provided in the question:

    P (Master card) = 27% = 0.27

    P (American express card) = 19% = 0.19

    P (Visa card) = 22% = 0.22

    P (Master and American express card) = 9% = 0.09

    P (Visa and master card) = 14% = 0.14

    P (American express and visa card) = 6% = 0.06

    Now,

    The probability of selecting a family that has either a Visa card or an American Express card

    = P (Visa card) + P (American express card) - P (Visa and American express card)

    = 0.22 + 0.19 - 0.06

    = 0.35

    or

    = 0.35 * 100% = 35%
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