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Mathematics
Elliana Baker
24 March, 11:04
2i^4-5i^3+3i^2+√-81 rewritten in a+bi form?
+1
Answers (
1
)
Dean Kidd
24 March, 13:09
0
-1 + 14i.
Step-by-step explanation:
i^2 = - 1.
i^4 = i^2 * i^2
= - 1 * - 1 = 1.
i^3 = i^2 * i = - i.
√-81 = i√81 = 9i.
So
2i^4-5i^3+3i^2+√-81
= 2 - (5 * - i) - 3 + 9i
= - 1 + 5i + 9i
= - 1 + 14i.
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