Latoya, Milan, and Hong served a total of 154 orders Monday at the school cafeteria. Latoya served 10 more orders than Milan, Hong served 4 times as many orders as Milan. How many orders did they each serve?

Orders served by Latoya, Milan and Hong are 34, 24, 96 respectively.

Solution:

Given, Latoya, Milan, and Hong served a total of 154 orders Monday at the school cafeteria.

Let orders served by Latoya ne a, orders served by Milan be b and orders served by hong be c.

Then, a + b + c = 154 ⇒ (1)

Latoya served 10 more orders than Milan, ⇒ a = b + 10

Hong served 4 times as many orders as Milan. ⇒ c = 4b

We have to find how many orders did they each serve?

Now, substitute a and c values in (1)

(b + 10) + b + 4b = 154

b + b + 4b = 154 - 10

6b = 144

b = 24

Then, a = 24 + 10 = 34 and c = 4 x 24 = 96.

Hence, orders served by Latoya, Milan and Hong are 34, 24, 96 respectively.