Ask Question
6 April, 17:38

Suppose you have gone bowling with an excellent player who bowls a strike (i. e. when they hit all of the pins) 73% of the time. By the fourth frame, this person realizes that they can clinch first place in a local tournament by bowling 3 consecutive strikes. What is the likelihood of this happening

+3
Answers (1)
  1. 6 April, 19:45
    0
    The probability of bowling 3 consecutive strikes is 0.3890.

    Explanation:

    On any given turn, this player has a 73% chance of bowling a strike. Hence:

    Probability of bowling a strike = P (S) = 73% = 0.73

    We need to find the probability of this player bowling 3 consecutive strikes. This is computed as follows:

    Probability of bowling 3 consecutive strikes

    = Probability of bowling first strike x Probability of bowling second strike x Probability of bowling third strike

    = P (S) x P (S) x P (S)

    = 0.73 x 0.73 x 0.73

    = 0.3890
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Suppose you have gone bowling with an excellent player who bowls a strike (i. e. when they hit all of the pins) 73% of the time. By the ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers