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The sum of the ages of an uncle and nephew 2 years ago was 40. In 2 years time from now the age of the uncle will be 3 times that of his nephew by then. Find their ages now.

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  1. Today, 11:56
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    x = 34, and y = 10.

    The age of the uncle is 34 years and

    The age of the nephew is 10 years now.

    Step-by-step explanation:

    Let x and y represent the ages of the uncle and nephew now respectively.

    Given that;

    The sum of the ages of an uncle and nephew 2 years ago was 40

    (x-2) + (y-2) = 40

    x+y - 4 = 40

    x+y = 40+4

    x+y = 44 ... 1

    In 2 years time from now the age of the uncle will be 3 times that of his nephew by then.

    (x+2) = 3 (y+2)

    x+2 = 3y+6

    Collecting the like terms;

    x-3y = 6-2

    x-3y = 4 ... 2

    Solving the simultaneous equation;

    Subtracting equation 2 from 1

    x+y - (x-3y) = 44-4

    y+3y = 40

    4y = 40

    y = 40/4 = 10

    y = 10

    Substituting y = 10 into equation 1;

    x + 10 = 44

    x = 44-10

    x = 34

    The age of the uncle is 34 years and

    The age of the nephew is 10 years now.
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