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19 February, 15:06

What is f (5) if f (1) = 3.2 and f (x+1) = 5/2?

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  1. 19 February, 17:11
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    Solution is given below

    Step-by-step explanation:

    f (x+1) = 2.5f (x) is an example of a recursion formula

    Use what we know about f (1) to find f (2). Then use f (2) to find f (3), etc.

    f (1) = 3.2

    f (2) = f (1+1) = 2.5f (1) = 2.5 (3.2) = 8

    f (3) = f (2+1) = 2.5f (2) = 2.5 (8) = 20

    f (4) = f (3+1) = 2.5f (3) = 2.5 (20) = 50

    f (5) = f (4+1) = 2.5f (4) = 2.5 (50) = 125

    and for f (x+1) = 5/2

    f (x + 1) = (5/2) (f (x))

    f (1 + 1) = (5/2) (3.2)

    f (2) = 8
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