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9 June, 23:37

Approximately how many times greater is 6 x 10^-5 than 5 x 10^-9

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  1. 10 June, 01:48
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    Answer:First, let's solve the first equation. Multiply 10 with 6 first:

    6*10=60

    Then subtract 5:

    60-5=55

    Now let's solve the second one. Multiply 5 with 10:

    5*10 = 50

    Then subtract the 9:

    50-9=41

    55 and 41 rounded to the nearest tens place are 60 and 40 ... but I can approximate how many times bigger one number is from the other because they're both under 100. Unless this was meant to have exponents, in which case, follow these steps:

    6^10=1,000,000

    1,000,000-5 = 999,995

    5^10=100,000

    100,000-9=99,991

    In the case of exponents, 999,995 is about 10 times greater than 99,991.
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