For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 72 N acts on a certain object, the acceleration of the object is 8 m/s^2. If the acceleration of the object becomes 10 m/s^2, what is the force?

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Mathematics

Mini Mini

16 December, 14:25

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 72 N acts on a certain object, the acceleration of the object is 8 m/s^2. If the acceleration of the object becomes 10 m/s^2, what is the force?

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Carter Cross · Answer 1

Step-by-step explanation:

If two variables are directly proportional, it means that an increase in the value of one variable would cause a corresponding increase in the other variable. Also, a decrease in the value of one variable would cause a corresponding decrease in the other variable.

For a moving object, the force acting on the object varies directly with the object's acceleration. Let F represent force and A represent acceleration, if we introduce a constant of variation, k, then the expression becomes

F = kA

When a force of 72 N acts on a certain object, the acceleration of the object is 8 m/s^2. This means that

72 = 8k

k = 72/8 = 9

The equation becomes

F = 9A

If the acceleration of the object becomes 10 m/s^2, then the force would be

F = 9 * 10

F = 90N