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27 September, 03:15

The perimeter of a rectangle is P = 2L + 2W, where L is the length and W is the width. If the perimeter is 200 feet and the length is 40 feet more than the width, what are the dimensions?

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  1. 27 September, 05:52
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    Length - 70

    Width - 30

    Step-by-step explanation:

    Let the width be x

    Length is 40 more than width which makes length = x + 40

    Perimeter = 2L + 2W

    2 (x + 40) + 2 (x)

    Open brackets

    2x + 80 + 2x = 4x + 80

    Perimeter = 200

    200 = 4x + 80

    4x = 200 - 80

    4x = 120

    x = 120/4

    x = 30

    Width = 30

    Length = x + 40 = 70

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