two cards are drawn without replacement from a standard deck of 52 playing cards. what is the probability of choosing a diamond and then without replacement another diamond? express your answer as a fraction or decimal number rounded to four decimal places.

Question

Mathematics

Humberto Harrison

25 September, 08:09

two cards are drawn without replacement from a standard deck of 52 playing cards. what is the probability of choosing a diamond and then without replacement another diamond? express your answer as a fraction or decimal number rounded to four decimal places.

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Answers (1)

Know the Answer?

Jazlene Fry · Answer 1

1/17

Step-by-step explanation:

There are 13 diamond cards in a standard 52-card deck.

First drawing:

13 diamonds

52 total cards

After the first drawing you already took a diamond, so there are 12 diamonds left out of 51 total cards.

p (diamond and diamond) = 13/52 * 12/51 = 1/4 * 4/17 = 1/17