What are the intercepts of the function?

The x-intercepts are

Consider the function f (x) = x2 + 12x + 11.

x-intercepts:

0 = x2 + 12x + 11

0 = (x + 1) (x + 11)

The y-intercept is

y-intercept:

fo) = (0) 2 + 12 (0) + 11

Question

Mathematics

Davon Cherry

16 June, 05:15

What are the intercepts of the function?

The x-intercepts are

Consider the function f (x) = x2 + 12x + 11.

x-intercepts:

0 = x2 + 12x + 11

0 = (x + 1) (x + 11)

The y-intercept is

y-intercept:

fo) = (0) 2 + 12 (0) + 11

+5

Answers (1)

Know the Answer?

Chaim · Answer 1

x-int: (-1, 0), (-11, 0)

y-int: (0, 11)

Step-by-step explanation:

To find x-int, set equation equal to 0:

x² + 12x + 11

(x + 1) (x + 11)

x = - 11, - 1

To find y-int, set x = 0

f (0) = 0² + 12 (0) = 11

f (0) = 11

What are the intercepts of the function?The x-intercepts areConsider the function f (x) = x2 + 12x + 11.x-intercepts:0 = x2 + 12x + 110 = (x + 1) (x + 11)The y-intercept isy-intercept:fo) = (0) 2 + 12 (0) + 11

What are the intercepts of the function?

The x-intercepts are

Consider the function f (x) = x2 + 12x + 11.

x-intercepts:

0 = x2 + 12x + 11

0 = (x + 1) (x + 11)

The y-intercept is

y-intercept:

fo) = (0) 2 + 12 (0) + 11