A father's age is eight years more than three times his sons age. the mothers agee is eighteen years more than to times the sons age. What are the ages of the father, mother and son, if the mother is four years younger than the father

Question

Mathematics

Susan Frank

16 November, 07:24

A father's age is eight years more than three times his sons age. the mothers agee is eighteen years more than to times the sons age. What are the ages of the father, mother and son, if the mother is four years younger than the father

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Answers (2)

Know the Answer?

Francisco Baxter · Answer 1

based on my knowledge the kid is 8. you solve the rest.

Miley Ponce · Answer 2

Ages of the father, mother and son are 50, 46 and 14 respectively.

Step-by-step explanation:

Step 1:

Let the age of the son be x. From given details, form equations.

Then age of father = 3x + 8

Age of mother = (3x + 8) - 4 = 3x + 4

Also, Age of mother = 18 + 2x

Step 2:

Equate the 2 equations for the age of mother.

⇒ 3x + 4 = 18 + 2x

⇒ x = 18 - 4 = 14

⇒ Age of father = 3x + 8 = 3*14 + 8 = 50

⇒ Age of mother = 3x + 4 = 46