8/5+3y=6y-1/5 the solution is y=

y = - 5 / 2 or y=1

Step-by-step explanation:

Step 1: Cross-multiply.

8 / 5+3y = 6y-1 / 5

(8) * (5) = (6y-1) * (5+3y)

40=18y^2+27y-5

Step 2: Subtract 18y^2+27y-5 from both sides.

40 - (18y^2+27y-5) = 18y^2+27y-5 - (18y^2+27y-5)

-18y2-27y+45=0

Step 3: Factor left side of equation.

-9 (2y+5) (y-1) = 0

Step 4: Set factors equal to 0.

2y+5=0 or y-1=0

y = - 5 / 2 or y=1

Answer:

y = - 5 / 2 or y=1