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22 February, 09:39

three consecutive integers are such that three times the smaller is fourteen more than the largest. find the integers

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  1. 22 February, 10:13
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    8, 9, 10

    Step-by-step explanation:

    Let the three consecutive numbers be;

    First number = a

    Second number = a + 1

    Third number = a + 2

    Three times the smaller number is fourteen more than the largest.

    i. e 3a = (a + 2) + 14

    3a = a + 16

    3a - a = 16

    2a = 16

    a = 16 : 2 = 8

    So the first number is 8 and the next two consecutive numbers are 9 and 10.
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