Find the center and the radius of the circle with the equation x^2+6x+y^2+4y+10=1

Question

Mathematics

Alexus Walsh

17 October, 20:24

Find the center and the radius of the circle with the equation x^2+6x+y^2+4y+10=1

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Answers (2)

Know the Answer?

Aracely · Answer 1

The center is (-3, - 2) and the radius is 2.

Step-by-step explanation:

x² + 6x + y² + 4y + 10 = 1

x² + 6x + y² + 4y = - 9

Complete the squares.

x² + 6x + 9 + y² + 4y + 4 = - 9 + 9 + 4

(x + 3) ² + (y + 2) ² = 4

(x + 3) ² + (y + 2) ² = 2²

The center is (-3, - 2) and the radius is 2.

Lesly · Answer 2

The center is (-3, - 2) and the radius is 2.

Step-by-step explanation:

x² + 6x + y² + 4y + 10 = 1

x² + 6x + y² + 4y = - 9

Complete the squares.

x² + 6x + 9 + y² + 4y + 4 = - 9 + 9 + 4

(x + 3) ² + (y + 2) ² = 4

(x + 3) ² + (y + 2) ² = 2²

The center is (-3, - 2) and the radius is 2.