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14 December, 14:04

Which equation has the solutions x = 5 ± 2 square root 7 all over 3

1. 3x2 - 5x + 7 = 0

2. 3x2 - 5x - 1 = 0

3. 3x2 - 10x + 6 = 0

4. 3x2 - 10x - 1 = 0

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Answers (1)
  1. 14 December, 16:33
    0
    4. 3x^2 - 10x - 1 = 0

    Step-by-step explanation:

    You can write the quadratic from the roots:

    0 = (x - (5-2√7) / 3) (x - (5+2√7) / 3)

    = (x - 5/3) ^2 - (2√7/3) ^2

    = x^2 - 10/3x + 25/9 - 28/9

    = x^2 - 10/3x - 1/3

    Multiplying by 3 gives ...

    0 = 3x^2 - 10x - 1
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